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A 1.00L buffer solution has the following concentrations: 1.50M formic acid and 1.25M sodium formate. The pK, for formic acid
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Answer #1

formic acid concentration = 1.50 M

concentration of sodium formate = 1.25 M

pKa = 3.74

pH = pKa + log [salt / acid]

   = 3.74 + log [1.25 / 1.50]

pH = 3.66

concentration of NaOH = 0.20

pH = pKa + log [salt + C / acid - C]

     = 3.74 + log [1.25 + 0.20 / 1.50 - 0.20]

pH = 3.787

pH change = 0.127

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