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5. 10/24 points Previous Answers Calculate the change in pH to 0.01 pH units caused by adding 10. mL of 2.58-M NaOH is added

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0.0 258 mde. 0.010 x 2.58 mot/L Mole NaOH O,570 x O.189 male/L 0.189 M NH= 570 O.10773 mele. pOH 0.10733 - 0.0258 + O.0258 po

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