Question

Calculate the pH of each of the solutions and the change in pH to 0.01 pH units caused by adding 10.0 mL of 2.31-M HCI to 620. mL of each of the following solutions Change is defined as final minus initial, so if the pH drops upon mixing the change is negative a) water pH before mixing 7.00 pH after mixing- 1.42 pH change = X 5.53 1- b) 0.186 M C2H302 pH before mixing- 9.01 pH after mixing 5.34 3.67 pH change- c) 0.186 M HC2H302 pH before mixing 2.79 pH after mixing- 1.99 pH change ) 1.31 d) a buffer solution that is 0.186 M in each C2H20 and HC2H20 pH before mixing-4.79 pH after mixing 4.56 pH change 18

Answer 1

Solution

Given that

Solution- GRven thot Adding → 10.0 mL Ofe.3l-MHC」 023 mo of Ht --log [ 0.0372

min C oung e S. s3 0 0I

→ adding 0.0372 molan . H+derme dectade to acoic acid H3 COO H 0.637「 ;" ch ang e _-3167

c) 186 HC2 H 02 ー CH3 COO+H "X CH3 COOH → O 186 0,186 P Bepo chang e ch and HHro2

O 186 0.186 0.986 do He lefd O 186 0 02 0 186-0 0372 0, 223Z pChoun