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A fuel has a chemical formula of C2N4H6O (Mfuel= 264 kg/mol). Combustion of this fuel leaves half of the available carbon atoms to become CO instead of CO2. The fuel is combusted with an AF ratio of 5. Determine the theoretical and excess air of this process.

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M.W 264 klen Fuel 2Ny He0r + 3H20 200 2 002 +4NO2 3 M20 2. Pucl Consumed thein 을 b Basis Suadion (Z Seachon CD nd each kmoleRNO 1 kmale C2N4 HeO2 13 02 kmele than 264 Ky C2N4 H0 13 x32 k 13x32 ky 2 N2M02 2 E O.3939 k Or s04 (mas) than for 1 ks PuettBut N273% (onteinins Air basis Mole the on 79 kmol N, 7 79X2 ks N2 l06 Air kMole , 27 21 x 3 2 21 kmol Molar mass N 28, 0 32tha we Canclule thed 2212 K N2 2884 K Air or 2 884 k Air 2 884 Air ky 672 2884 ky Ai 2884 O.7272 k 02 3 x o7272 ks AiA 672 3.Air to td Ratio Atr Mass AF Mass Air Ma ss 5kg Sxik Air (Supply Air Air The ontial exuss (5-3.1203) - 118791 exass Ai exuss A

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