The product gas from a liquid fuel (C_6 H_x) combustion reaction has the following dry-basis molar composition: 12.97% CO_2, 1.44% CO, 4.32% O_2, and 81.27% N_2.
Assume no solid or liquid products! Liquid fuel disappears completely.
calculate the Ratio of carbon and hydrogen. What is x?? (C_6 H_x)
what is %(percent Excess Air)?????? and Excess air??
Please explain in detail.
The product gas from a liquid fuel (C_6 H_x) combustion reaction has the following dry-basis molar...
Two fuel gases are mixed together prior to being burned with air in a furnace to produce a flue gas with the following composition: CO_2 7%, CO 1%, O_2 7% & N_2 85% (on a dry basis). The analyses of the fuel gases are as follows: Fuel Gas A: CH_4 80%, N_2 20% Fuel Gas B CH_4 60%, C_2H_6 20%, N_2 20% All compositions are expressed on a mole basis. Calculate a The mole ratio of Gas A to Gas...
Problem 4 A fuel gas has a composition by volume of: 50% H2 , 6% CO2, 4% N2 , 40% CO. The dry exhaust gas analysis (% by volume) of the actual combustion process indicates 9.2% CO2, 0% CO, some O2. Recall that for gases, volumetric composition is the same as molar composition. (a) What air/gas ratio (by volume) is required for stoichiometric combustion? (m? air/ m² fuel gas) (b) What air/gas ratio (by volume) has actually been used? (m’...
From a combustion process that used ethane (C2He) as a fuel, the ORSAT analysis of the stack gases on a nitrogen free basis is as follows: Component CO2 CO O2 Xi (molar basis) 0.289 0.191 0.520 Determine: 1.1. Percentage of the fuel that produced CO 1.2. Percentage of the fuel that produced CO 1.3. Selectivity of CO: with respect to CO 1.4. Theoretical Oxygen. 1.5. Percentage Excess Air 1.6. Amount of Nitrogen produced 1.7. Composition of flue gas (molar) on...
A liquid fuel containing C, H and O, was burned completely using excess air. The Orsat analysis of the combustion gas shows 4.48% CO2, 11.21% O2 and 84.31% N2, And the molal humidity of the product gas is 0.179 mol water vapor per mol of dry gas. Calculate % composition by weight of the liquid fuel.
A liquid fuel containing C, H and O, was burned completely using excess air. The Orsat analysis of the combustion gas shows 4.48% CO2, 11.21% O2 and 84.31% N2, And the molal humidity of the product gas is 0.179 mol water vapor per mol of dry gas. Calculate % composition by weight of the liquid fuel.
A liquid fuel containing C, H and O, was burned completely using excess air. The Orsat analysis of the combustion gas shows 4.48% CO2, 11.21% O2 and 84.31% N2, And the molal humidity of the product gas is 0.179 mol water vapor per mol of dry gas. Calculate % composition by weight of the liquid fuel.
A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of the combustion gas is 5.34% CO2, 13.23% O2 and 81.43% N2. The molal humidity of the product is 0.179 mol water vapor/mol of dry gas. Calculate percent composition by weight of the liquid fuel.
A liquid fuel containing Co and H2, was burned using excess air. Its Orsat analysis of the combustion gas is 5.34% CO2, 13.23% O2 and 81.43% N2. The molal humidity of the product is 0.179 mol water vapor/mol of dry gas. Calculate percent composition by weight of the liquid fuel.
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene, and the balance water. Composition Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H20/mol dry gas). Component Mole % (Wet basis) Mole % (Dry basis) Methane 81.5 90.22 Ethane 5.74 6.35 Ethylene 3.09 3.42 Water 9.66 mol H20/mol dry gas: Click if you would like to Show Work for this question: Open Show...
Problem 4.84 Combustion Mixture A gas contains 75.0 wt% methane, 10.00 wt% ethane, 5.00 wt% ethylene, and the balance water. Composition Calculate the molar composition of this gas on both a wet and a dry basis and the ratio (mol H20/mol dry gas). Component Mole % (Wet basis) Mole % (Dry basis) Methane 81.5 90.22 Ethane 5.74 6.35 Ethylene 3.09 3.42 Water 9.66 mol H20/mol dry gas: Click if you would like to Show Work for this question: Open Show...