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Resources Check Answer Question 24 of 24 > Write the half-reactions as they occur at each electrode and the net cell reaction
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Answer #1

1)

At anode oxidation occurs.

Here In(s) is being oxidised to In3+(aq)

So, the reaction at anode is:

In(s) -> In3+(aq) + 3e-

2)

At cathode reduction occurs.

Here Cd2+(aq) is being reduced to Cd(s)

So, the reaction at cathode is:

Cd2+(aq) + 2e- -> Cd(s)

3)

Balance the number of electrons to 6 in each case.

2 In(s) -> 2 In3+(aq) + 6e-

3 Cd2+(aq) + 6e- -> 3 Cd(s)

Combine both reaction to get net cell reaction which is”

2 In(s) + 3 Cd2+(aq) -> 2 In3+(aq) + 3 Cd(s)

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