answer) we know the formula
y(x,t)=Acos(kx+t).......1)
=2pif=2pi*v/=2pi*8m/s/0.320m=157 s-1
and k=2pi/=2pi/0.320=19.625 m-1
so putting the values in equation 1 we have
y(0.360,0.150s)=0.0700m*cos(19.625 m-1*0.360m+157s-1*0.150s)=0.0487m=4.87cm
so the answer is 4.87 cm
We consider transverse waves on a string that have a wave speed of 8.00 m/s, amplitude...
We consider transverse waves on a string that have a wave speed of 8.00 m/s, amplitude 0.0700 m, and wavelength 0.320 m. The waves travel in the -x-direction, and at t=0 the x=0 end of the string has its maximum upward displacement. Find the transverse displacement of a particle at x=0.360 m at time t =0.150 s. Give your answer in centimeters.
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Transverse waves on a string have wave speed 8.00 m/s, amplitude 0.0700 m, and wavelength 0.320 m. These waves travel in the x direction, and at t = 0 the x = 0 end of the string is at y = 0 and moving downward. A) Find the frequency of these waves. B) Find the transverse displacement of a point on the string at x2 = 0.120 m at time t2 = 5.00×10−2 s .
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ctur SmartVa IT HelpSynergy SFUSD bookmarks Water Recyding & ReThe EPA Online LibraD D | Question 4 1 pts We consider transverse waves on a string that have a wave speed of 8.00 m/s, amplitude 0.0700 m, and wavelength 0.320 m. The waves travel in the -x-direction, and at t-0 the x-0 end of the string has its maximum upward displacement. Find the transverse displacement of a particle at x-0.360 m at time t -0.150 s. Give your answer in...
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Transverse waves traveling along a string have the following properties. Amplitude of the wave = 2.75 mm Wavelength of the wave = 0.150 m Speed of the wave = 408 m/s Determine the time for a particle of the string to move through a total distance of 1.50 km.
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