Question

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q′ separated by a distance d is |F|=K|QQ′|/d^2, where K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -18.5 nC , is located at x1 = -1.655 m ; the second charge, q2 = 34.5 nC , is at the origin (x=0.0000).

What is the net force exerted by these two charges on a third charge q3 = 52.5 nC placed between q1 and q2 at x3 = -1.235 m ? Your answer may be positive or negative, depending on the direction of the force.

Answer 1

NOTE: like charges repel each other and unlike charges attract each other.

So a negatively charged body will attract another positively charged body but will repel another negatively charged body.

Please feel free to ask in case of any doubt and discrepancies.

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Answer 2

This video explains it and has the answer! https://youtu.be/NZe1L3Uhrsc