I could use some help with the five following questions regarding epidemiology.
Q.1 attack rate of the pizza eatemn is= no of people eaten pizza/total no of people
total no of people ate pizza=39=14=53
total people=50=42=92
hence the attack rate of pizza eaten =53/92
Q.2 answer is 12 days as the incubation period is the time duration between the expose of the disease pathogen into the body and the the time when the first symptome of the disease is shown
hence incubation period in this case is 17-5=12 days.
Q.3. Option 1 is correct, as This graph is the type of single exposure and common vehicle outbreak type as its plotted betwen the no .of cases with respect to the time of onset in the common vehicle, that is passengers and the crew members
Q.4 Option C is correct as this class has eaten both the Pizza and the icecream
as the chances of getting infective are likely tobe:
P=39/92=0.42
P+I=39/52=0.75
I=11/15=0.73
P=Pizza
I= Ice cream
Hence P+I is most likely to be infective
Q.5.during the incubation period the symptoms of the disease try to appear
I could use some help with the five following questions regarding epidemiology. Moving to another question...
A statistical risk for infectious disease. Please show work and explain Calculate the attack rate for person who did eat pizza. Ate Ice Cream Did Not Eat Ice Cream DIARRHEA TOTAL ATE PIZZA DID NOT EAT PIZZA ! DIARRHEA 39 TOTAL 52 15 14 40 30 O 39/52 50/67 O 53/92 O 14/40 O 20/45
1. Using the table from the last question, calculate the overall attack rate in persons who did not eat ice cream. Ate ice cream Diarrhea 39 11 Total 52 15 Did not eat ice cream Diarrhea 14 Total 40 30 Ate pizza Did not eat pizza
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