Question

Make a neat presentation. 1.(10) In a Nucleophilic Aliphatic Substitution reaction, an unknown alkyl halide, RBr, reacts with water to produce an alcohol and HBr according to the following equation: RBr + H2O ROH + HBO Representative experimental data on the rate of the reaction is given in the table below. Experiment # [RBr] [H0] Relative Rate 0.01 0.02 0.01 0.01 0.01 0.02 (a)(5) Write the rate expression for this reaction. You must clearly explain why this data supports your conclusion. (b)(5) What is the order of this reaction? Explain why.

Answer 1

a) 5 rate = k [ R Br] ² [ H20] since, eu 1 = ( 6.)n where, n = order on of reaction o for RBr - = 6)" OR + 2 = (0.02 2 lo.01 n= 1 n = 1 dota R Br.] Similarly, for Ho - Ź = (2) n = -1 . r = [H2O7 - Combining both , late expression becomes reate = k [RB] [160]

15 Order of reaction will be - Zero Order reaction on rate = k [ RBr] [ tho] - o n = 1 + (-1) n = 0 where, n = order of reaction This is because we know that - I Order of reaction is the sum of power of concentration in experimental "rate law. ug M, A + N₂B P. & late = K[A] [B]Y o order of reaction (n) = x+y