Question

2.Two wires hold a painting up on the wall. The angles are given in the diagram. The tension in wire 2 is 210 N a) What is the tension in wire 1? Show all problem solving steps 35 55 wire 1 wire 2 b) What is the weight of the painting?

Answer 1

From the figure, T_1 sin 35 degree = T_2 sin 35 degree rightdoublearrow T_1 = 210 times sin^55 degree/ sin 35 degree = 299.9 N almostequalto N Tension in the wire 1 is T_1 = 300 N from the figure, T^1 = W W = T_1 cos 35 degree + T_2 cos 55 degree = 300 cos 35 degree + 210 cos 55 degree = 366.2 N Weight of the painting is W = 366.2 N

a) From the figure, $T_1\sin35\degree=T_2\sin55\degree \Rightarrow T_1=210*\frac{\sin55\degree}{\sin35\degree}=299.9\,N\approx 300\,N$

Tension in the wire 1 is $T_1=300\,N$

b) From the figure,  $T'=W$$\Rightarrow W=T_1\cos35\degree+T_2\cos55\degree=300\cos35\degree+210\cos55\degree=366.2\,N$

Weight of the painting is $W=366.2\,N$