Question

You may want to reference (Pages 259-263) Section 7.10 while completing this problem. Part A Determine how many kilojoules are released when 68.8 g of oxygen reacts via the following reaction: 2CH, OH(1) + 30,() - 200,() + 4H, O(1), AH = -726 kJ AED RO? Submit Request Answer Part B Determine how many kilojoules are absorbed when 316 g of Ca(OH), reacts via the following reaction: Ca(OH), (8) CaO(s) + H2O(1), AH = +65.3 kJ %0AED Om ? Submit Request Answer Provide Feedback

Answer 1

part A 2 CH ₂ OH + 30₂ - 2102 & uth₂0 BH=-726k5 226 KT of for every & moles of orggen energy is released. Mas o oreggen = 68.89 moles of mars oxygen - molar mass 9 68.8 32 - 2.15 moles. 8 for 3 moles - 2015 moles 226 kJ ? 20158726 a = 520.3.15 At for 2015 moles -

for 68.8 9 ob released. ₂ 52003 kJ d energy & peat B Ca Cott), Go + H₂O 4t = 6503 kJ 65.3 kJ ob energy is for 1 mob do Caloh) - absorbed. Mass of Ca (OH) moles of Glotta = 3169 = mass moled mass 316 76 - 4.27 moles. I mole de Glot 4.27 moles - 65.3 kJ a absorbed - 4.27 x 65-3 = 278.85 kJ 278-85 kJ de evengy is absorbed.