Question

Name: (6) The following were values obtained in a test to measure a male subjects Lab TA: INITIALREADINOS FINAL READINGS SAMPLE Abs. 560nm Iron STD SUBJECT 0.099 Abs. 560nm 0.014 0.388 0.138 The following were values obtained in a test to measure the same subjects' UIB INITIALREADINGS EINAL READINGS SAMPLE Abs. 560nm Iron STD SUBJECT 0.112 Abs. 560nm 0.385 0.280 0.011 a) Using the above test results, calculate the following indices (show calculations and don't forget units!) (8 pts) Index Serum iron Answer (with units) Calculation UIBC TIBC Transferrin saturation

Answer 1

Serum iron = [(A¹- A⁰)test / (A¹ - A⁰)std] x std iron conc.

* standard iron conc = 500 ug/dl

Serum iron = [(0.138 - 0.099) / (0.388 - 0.014)] x 500

serum iron = (0.039 / 0.374) x 500 = 52.13 ug/dl

UIBC = std iron conc - {[(A”- A’)test / (A”- A’)std] x std iron conc}

UIBC = 500 - {[0.280 - 0.112 / 0.385 - 0.011]x 500}

UIBC = 500 - {[0.168 / 0.374] x 500}

UIBC = 500 - 224.6 = 275.4 ug/dl

TIBC = serum iron + unsaturated iron-binding capacity

TIBC = 52.13 + 275.4 = 327.53 ug/dl

Transferrin saturation%= serum iron/TIBC X 100

Transferrin saturation%= 52.13/327.53 x 100 = 15.9%