Question

(Chapter 2-Part 2 Problem 2.74 K11 of 11 Constants Periodic Table Pelicans tuck their wings and free-fall straight down dive from a height of 17.0 m and cannot change its ▼ Part A escape? Assume the fish is at the surface of the water Express your answer using two significant figures. K Return to AssignmentProvide Feedback

Answer 1

velocity when the pelican reaches the surface

$v^{2}=u^{2}+2as$

$v^{2}=0^{2}+2*9.81*17$

$v= 18.263 m/s$

The distance when the pelican has to be spotted by the fish,

$s = vt -\frac{1}{2}at^{2}$

$s = 18.263*0.25 -\frac{1}{2}*9.81*0.25^{2}$

$s = 3.3395 m$