On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg length 81.1 cm and diameter acceleration due to gravity, g 9.81 m.
Homework Answers
area of rod = (pi) (.024/2)^2*0.811 = 0.0003669 m^2
mass = area * density
= 0.0003669 * 7800= 2.86 kg
weight = mass*gravity
= 2.86 kg* 9.81 m/s^2
= 28.07 N
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