Question

When Chlorine gas is added to acetylene gas, 1,1,2,2-tetrachloroethane is formed: 2Cl_2(g)+C₂H_2(g)--> C₂H₂Cl_4(l)

How many grams of chlorine will be needed to make 75.0 grans of C₂H₂Cl₄?

Answer 1

2 moles Cl₂ required to produce 1 mole C₂H₂Cl₄

Molar mass of C₂H₂Cl₄ is 167.8493 g/mol

moles in 75 g of C₂H₂Cl₄ = 75 g / 167.8493 g/mol = 0.44682938802 mol

moles Cl₂ required = 2 x 0.44682938802 = 0.89365877605 mol

mass of Cl₂ required = moles Cl₂ x molar mass of Cl₂ = 0.89365877605 mol x 70.9060 g/mol = 63.3657691751 g ~ 63.4 g

Answer: grams of chlorine will be needed to make 75.0 grans of C₂H₂Cl₄= 63.4 g

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