Question

The mass of one uranium atom is 4.0 x 10-26 kg. How many uranium atoms are there in 5.0 g of pure uranium? 1.25 x atoms Use the given information to equate the ratios of the number of uranium atoms in the given mass of pure uranium and of 1 atom to its mass. eBook 2. -0.62 points Tipler 1.PO66 Notoe O Ask Your Teache | During a thunderstorm, a total of 1.8 inches of rain falls. How much water fals on one acre of land? (1 mi2 = 640 acres) Express your answer in the following ways. (a) cubic inches in3 (b) cubic feet ft3 (c) cubic metdrs m3 (c) kilograms kg (Note that the density of water is 1000 kg/m3.) eBook

Answer 1

M_u = 4.0 times 10^- 26 kg m = 50.g = 5.0 times 10^- 3 kg Uranium Atoms = m/m_u = 5.0 times 10^- 3 kg/4.0 times 10^- 26 kg = 1.25 times 10^23 1 Inches of rain means depth of rain is inches on A particular area Therefore volume = (Area) (Depth) v = (1 mi^2) (1 inch) = (63360 inch)^2 (1 inch) = 4.014 times 10^9 ln^3 v = (1 mi)^2 (l in) = (1609.34m)^2 (0.025Hm) = 6.58 times 10^4 m^3 mass Rho v = (Density) (Volume) = (1000 kg/ m^3) (6.58 times 10^4) = 6.58 times 10^7 kg

I will be glad to see your comment if you have any query and thumb up if you are satisfied. Thanks....