Question

Calculate the pH at 0, 25.0, 50.0, 75.0, 100, and 125% titration in the titration of both
protons of the diprotic acid H2A with 0.100 M NaOH, starting with 100 mL of 0.100 M H2A.
Ka1 = 1.0 × 10−3, Ka2 = 1.0 × 10−7.

I hv the scheme but I dont know they get the volume from % and how to determine the 1st n 2nd eq point

21. oxt calculate the front ionization of first proton of WyA. Since CHA) is just equal to the actit en fon med wat te used. TH') - HA11.02100.100 1.0 . 102 pH 2.00 25.ox: This is halfway to the first equivalence point and CHA] CHA] 130 AL? (0.100 MX 50.0 ML 5.00 moleach) DHK , lugKCHA 17EM,A]) - 3.00 + 109 15.00/5.00). 3.00 50.: This is at the 1st equivalence point. A11 MyA has been converted to HA - 10.0 mal in 200 m). #*). V 1.0 10-2.1.0 x 10-7.1.030- pH 5.00 75.68: This is halfway between the two equivalence points, and [A (150 ml) (5.00 mol each) DH = log ICA-MP3) = 7.00.109 65.00/5.00) - 7,00 100.0%: A11 the HA has been converted to t 10.0 mol in 300 mL) CA). 0.0333 42 ,0 HAOH CHAO/A>) (2) - (1.0 10-20 10-.1.0 x 100% 6.0 x 10-7.04). 6.0x 10-7 * 0.0333 3.8 - 105 POH 4.24: DH . 9.76 (200 ml)