1)
Molar mass of Na = 22.99 g/mol
mass(Na)= 84.9 g
use:
number of mol of Na,
n = mass of Na/molar mass of Na
=(84.9 g)/(22.99 g/mol)
= 3.693 mol
Molar mass of Cl2 = 70.9 g/mol
mass(Cl2)= 53.2 g
use:
number of mol of Cl2,
n = mass of Cl2/molar mass of Cl2
=(53.2 g)/(70.9 g/mol)
= 0.7504 mol
Balanced chemical equation is:
2 Na + Cl2 ---> 2 NaCl
2 mol of Na reacts with 1 mol of Cl2
for 3.693 mol of Na, 1.846 mol of Cl2 is required
But we have 0.7504 mol of Cl2
so, Cl2 is limiting reagent
Answer: Cl2
2)
Molar mass of NaCl,
MM = 1*MM(Na) + 1*MM(Cl)
= 1*22.99 + 1*35.45
= 58.44 g/mol
According to balanced equation
mol of NaCl formed = (2/1)* moles of Cl2
= (2/1)*0.7504
= 1.501 mol
use:
mass of NaCl = number of mol * molar mass
= 1.501*58.44
= 87.7 g
Answer: 87.7 g
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