If we take the bottom of your window as the initial position and ground as the final position and use the kinematic equation, v^2 - u^2 =2as, we have, initial velocity, u = v_b, final velocity,v = v_ground, acceleration, a = g and displacent, s = h_b. Thus,
(v_ground)^2 - (v_b)^2 = 2*g*h_b
Or, (v_ground)^2 = (v_b)^2 + 2*g*h_b
Thus, v_ground = [(v_b)^2 + 2*g*h_b]
Home mework 2-1 lower Pot Falling Past a Window く) 2017 Constants I Periodic Table Express...
As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is Lw. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g. Assume that the flower pot was dropped by someone on the floor above you (rather than thrown downward). From what height h above the bottom...
Constants | Periodic Table Part A As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t, and the vertical length of your window is L. Take down to be the positive direction, so that downward velocities are positive and the acceleration due to gravity is the positive quantity g From what height h above the bottom of your window was the flower pot dropped? Express your answer in...
As you look out of your dorm window, a flower pot suddenly falls past. The pot is visible for a time t and the vertical length of your window is L. Take down to be the positive direction, so that downward velocities are positive and the aoceleration due to gravity is the positive quantity g lfthe bottom of your window is a height h, above the round, what is the velocity %round ofthe pot as it hits the You may...