Question

Consider the concentration cell in which the metal ion has a charge of +3, and the...

Consider the concentration cell in which the metal ion has a charge of +3, and the solution concentrations are:

dilute solution = 0.007 M

concentrated solution = 1.278 M

What is the predicted Ecell, using the Nernst equation? ____ V

Provide your response to three digits after the decimal.

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Answer #1

This cell contain same electrodes with
different electrolyte concentration .Such cells are known
as concentration cell.Current flow will happen by
flow of electrons from lower concentration half cell to
high concentration half cell.
Ecell = E0cell-0.0591/n log Q

This type of cell E0= 0 [since both are half cell of same metal]
So Ecell = -RT/nFlog Q** is the formula

Q is the reaction quotient = [product]/[reactant]
M3+(conc)(1.278 M) ---> M3+(dil)( 0.007 M)

number of electrons involved n =3** since charge of ions =+3
Thus ECell = -0.0592/3 log( 0.007 M)/(1.278 M)
= 0.0446 V
*****************

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