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19. A 0.290 gram sample of a weak base is titrated with a 0.150 M HCl solution. It takes 28.0 mL of the 0.150 M HCl solution
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Answer #1

Mal ar Baye IL =1000ML malarity X Vaume (91 Mal acid to boue 4.2 X10 molu hin melE acid 4.2 K1O3 me Base mars Mau - mular maS

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