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Question 11 A group of 42 college students from a certain liberal arts college were Type numbers in the boxes randomly sample
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Answer #1

Population Mean = 4.73

Sample Mean (x) = 5.31

Sample Std Dev (s) = 3.93

Sample Size (n) = 42

Alpha = 0.05

Null and Alternate Hypothesis

H0: µ = 4.73

Ha: µ <> 4.73

Test Statistic

t = (5.31 – 4.73) / (3.93/421/2) = 0.96

p-value = TDIST(0.96,42-1,2) = 0.3445

Result

Since the p-value is greater than 0.05, we fail to reject the null hypothesis.

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