Homework Answers
Since , sound level(L) = 10*log(I/Io) dB
So,
L2 - L1 = 10*log(I2/Io) - 10*log(I1/Io)
where, Io = 10^-12 W/m^2
I1 & I2 = sound intensity
given , L2 - L1 = 29.0 dB
So, 29.0 = 10*log(I2/Io) - 10*log(I1/Io)
29.0 = 10*log[(I2/Io)/(I1/Io)]
2.9 = log(I2/I1)
I2/I1 = 10^2.9
I2/I1 = 794
Therefore intensity of sound is increased by 794.
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