Here ,
electric field , E = 1500 N/C
theta = 25 degree
electric flux = E * Area * cos(theta)
electric flux = 1500 * 1 * cos(25 degree)
electric flux = 1346.5 N.m^2/C
the electric flux in a square meter is 1346.5 N.m^2/C
7) A uniform electric field of 1500 N/C is incident on the earth's surface at an...
In a particular region of Earth's atmosphere, the electric field above Earth's surface has been measured to be 150 N/C downward at an altitude of 230 m and 168 N/C downward at an altitude of 380 m. Calculate the volume charge density of the atmosphere, assuming it to be uniform between 230 and 380 m. (Hint: You may neglect the curvature of Earth. Why?) C/m eBook
In a particular region of Earth's atmosphere, the electric field above Earth's surface has been measured to bo 143 N/C downward at an altitude of 280 m and 16 NC downward at an altitude of 430 m. Calculate the volume charge density of the atmosphere, assuming it to be uniform between 280 and 430 m. (Hint: You may neglect the curvature of Earth. Why?) C/m3
An uniform electric field, E with a magnitude of Eo N passes through a square surface at an angle of a 41.1 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m × 2m, and the flux through the surface is measured to be 24.72 m, what is the magnitude of a the electric field, Eo?
0 -1 points SerPSE10 23 A OP019. A uniform electric field measured over a square surface with side length d = 16.5 cm makes an angle θ = 69.0° with a line normal to that surface, as shown in the figure below. My Notes Ask Your Teacher ere is a square horizontal surface with length and width d. The surfoce has a normal vertical axis at the center with a vector labeled vector E traveling from the center of the...
An uniform electric field, E. with a magnitude of passes through a square surface at an angle of α-32.5 degrees relative to a line on the surface, as shown in the figure below. The square measures 2m x 2m, and the flux through the surface is measured to be 21.4 What is the magnitude of the electric field, Eo? N-m
Suppose a square surface of side 0.10 m is placed in a uniform electric field of magnitude 50.0 N/C. If the angle between the field and the normal to the surface is 25.0°, what is the magnitude of the electric flux through the surface? O 4.5 Nm2/c O 0.45 N-m2/c o.50 N-m2/c o.21 N-m2/c
A uniform electric field measured over a square surface with side length d = 13.5 cm makes an angle θ = 67.50 with a line normal to that surface, as shown in the figure below. If the net flux through the square is 5.30 N·m2/C, what is the magnitude E of the electric field (in N/C)? N/C
7. A uniform electric field E 30 N/C exists parallel to the axis of a square shaped figure with sides L = 10cm . Calculate the electric flux through the slanted side of the figure, with the slope of the slanted side being 350, How does that flux compare to the flux through the vertical side on the left?
The electric flux from a uniform field through a flat surface is 7.80 N·m2/C when the field lines make an angle of 13.0º with the plane of the surface. What is the electric flux when the angle is changed to 77.0º? (Enter units as Nm^2/C or Vm
A uniform electric field of magnitude 3.50x104 N/C makes an angle of 47 ° with a plane surface of area 1.63x10-2 m2 What is the electric flux through this surface? N m2/C Submit Request Ans