Why is the radiation in a cavity as if it came from a "black body"?
A cavity can be treated as perfect absorber as whatever will come to it will completely pass it without being reflected at that point.The cavity was a reasonable way to model mathematically the electromagnetic fieldfor the radiation observed/measured from all bodies, it simplifies the mathematics, and the small hole allows for the radiation to come out and be measured. It should have the same spectrum as the one radiated from any part of the body. For thermodynamic considerations it makes no difference if the body is hollow or not. Equilibrium is equilibrium and should exist outside and inside. A small hole is the probe of what is happening inside.Suppose the cavity is held at a fixed temperature T and the radiation trapped inside the enclosure is at thermal equilibrium with the enclosure. The hole in the enclosure will allow some radiation to escape. If the hole is small, radiation passing in and out of the hole has negligible effect upon the equilibrium of the radiation inside the cavity. This escaping radiation will approximate black-body radiation that exhibits a distribution in energy characteristic of the temperature T and does not depend upon the properties of the cavity or the hole, at least for wavelengths smaller than the size of the hole
2. The maximum wavelength of an ideal black body cavity radiation absorption is 6000 A. a. If the emission of thermal radiation from the cavity becomes 3 times, then what is the maximum wavelength and temperature? b. If the emission of thermal radiation from the cavity becomes times, then what is the maximum wavelength and temperature?
7. What is the relation between temperature and intensity of black body radiation? 8. What is the relation between the temperature of a black body and the color of its radiation? 9. What is the closest thing to a black body in our everyday life? 10. What is the importance of Planck's radiation law for modern Physics?
8. Compute the ratio of the increase of intensity of black-body radiation at a wavelength of 641 nm for an increase of temperature from 1200 to 1500 K
A black body has an effective surface temperature of 450°C. Determine: (a) The total radiation energy (W/m2) that can be emitted by the black body (b) Determine total radiation energy (W/m%) that can be emitted by the black body within the 5-50 um wavelength region (c) The spectral blackbody emissive power of the black body at a wavelength of 10 um. 12
8. A black body has an effective surface temperature of 450°C. Determine: (a) The total radiation energy (W/m²) that can be emitted by the black body (b) Determine total radiation energy (W/m²) that can be emitted by the black body within the 5-50 um wavelength region (c) The spectral blackbody emissive power of the black body at a wavelength of 10 um.
QUESTION 1 10 points Save Answer A black body ejects all radiation. Thast is why iseems to be black True QUESTION 2 10 points Save Answer Select All incorrect definitions Newton Law of oonvection states that heat loss is inversely proporsional to the change in temperature Nahural convection depends on the velocity of fluids passing over the object O Suface Geomety and fuid velooity affects the heat transfer by convection Foroed convection depends to the nature of fiow of liquids...
Demonstrate that the intensity of radiation from a black body in equilibrium with radiation is given by I = 1/4 cu. also show that the Stefan-Boltzmann constant is σ = 1/4 ca with a = 7.56 x10 ^ -16, u is the density of the radiation energy
if the temperature of a black body is reduced by half, the amount of emitted radiation is reduced by a) 1/4 b) 1/2 c) 3/4 d) 1/16 Can you also explain how you find the answer please.
Why doesn't the dorsal body cavity have any serous fluid at all?
11) Consider an electromagnetic type radiation that is contained within a cavity and is in equilibrium with the walls of that cavity (cavity radiation) that can be seen as a hydrostatic system, whose internal energy density and the pressure p exerted under the cavity walls are given by 1 U V u(T) P= where V is the volume of the cavity and T is the temperature of the cavity walls. Considering the energy density u = aT', where a is...