(6) (I) (a) Heat absorbed from body if you eat 1 kg of snow at -15°C which your body warms to 37°C
= M * Ci * (0 – (-15)) + Mi * L + M * Cw * (37 – 0 )
(M = Mass of water; Ci = specific heat of ice; L= latent heat of fusion; Cw = sp. Heat of water)
= 1*2108*15 + 1*333000 + 1*4187*37
= 519539 J or 519.539 KJ (Answer)
(b) Heat absorbed from body if you eat 1 kg of snow at -15°C (melted by stove up to 2° C) which your body warms to 37°C
= M * Cw * (37 – 2 )
= 1* 4187 * 35
= 146545 J or 146.545 KJ (Answer)
(7) (a) Heat capacity C in terms of specific heat c:
C = m * c where m = mass of substance (Answer)
(b) Heat capacity of 1 kg of water = m * c = 1 kg * 4187 J/kg°C = 4187 J/°C (Answer)
(c) Heat capacity of 1 kg of water = m * c = 45 kg * 4187 J/kg°C = 188415 J/°C (Answer)
Thanks!!!
06. High-altitude mountain climbers do not eat snow, but always melt To see why, calculate the...
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