A force of 40 N is applied perpendicularly 30 cm from the pivot point. What is the torque?
a. |
1.2 N-m |
|
b. |
12 N-m |
|
c. |
120 N-m |
|
d. |
1200 N-m |
Solution-
As we know that
T = F * r * sin(theta)
Here T= torque, r= distance,F= force
So putting the values
=40N*0.3m*sin(90)
= 12 N-m
Option B is correct
A force of 40 N is applied perpendicularly 30 cm from the pivot point. What is...
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