The value of Kp at 390.°C for the reversible reaction given below is 7.95 × 10−3. Calculate the value of Kc at 390°C.
A(g) + B(g) |
a. |
6.3 × 10−12 |
|
b. |
3.0 × 10−14 |
|
c. |
0.432 |
|
d. |
3.4 × 1013 |
|
e. |
2.8 × 10−2 |
The value of Kp at 390.°C for the reversible reaction given below is 7.95 × 10−3....
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2. At 55°C, the equilibrium constant for the reaction N2(g) + 3H2(g) + 2NH3(g) is Kp=0.05. What is the equilibrium constants Kc and Kp for the reaction 4NH3 + 2N2(g) + 6H2(g)? Kp = 400 Kc = 7.62 x 10 3. For the reaction given below, 10.00 moles of A and 25.00 moles of B are placed in a 5.00-L container at 120 °C. A(g) +2B(g) → C(g) At equilibrium, the concentration of A is 0.5 mol/L. What is the...
Ozone is formed from oxygen by the following reaction: 3/2 O2(g) ⇌ O3(g) Kp = 3.4 x 10-38 at 220 K. Calculate the value of Kc.
Need answer and explanation please!
b. What is the rate law for the overall-reaction? -I %10 pts) The relatonship between Kp and Kc is given by K,-K,(m". a. Calculate Kc for PCIs(g) → PC13(g) + Cl2(g) given KP-229 at 425°C. b. The reaction of nitrogen and hydrogen occurs according to the reaction N2 (g)+ 3H2 (g) → 2NH3 (g). Determine Kp for this reaction given Ke-6 x 105 at 25 °C x0602 An- nnr -1
b. What is the rate...