Question

Benzene and toluene form nearly ideal solutions. The boiling point of pure benzene is 80.1°C. Calculate...

Benzene and toluene form nearly ideal solutions. The boiling point of pure benzene is 80.1°C. Calculate the chemical potential of benzene relative to that of pure benzene when χbenzene = 0.30 at its boiling point. If the activity coefficient of benzene in this solution were actually 0.93 rather than 1.00, what would be its vapor pressure?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer! Mole fraction of benzerne = x benzene - 0.3 The chinical potential of benzene con be colculated using the equation: ü(vo pour pressure) PA= P = re benzene sa bu e DOM ОUVC A px = laton, because Boiling point of pure bungene is 80.1°C P = 0.93

Add a comment
Know the answer?
Add Answer to:
Benzene and toluene form nearly ideal solutions. The boiling point of pure benzene is 80.1°C. Calculate...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 6. Benzene and toluene form nearly ideal solutions. The boiling point of pure benzene is 80.1°C....

    6. Benzene and toluene form nearly ideal solutions. The boiling point of pure benzene is 80.1°C. Calculate the chemical potential of benzene relative to that of pure benzene when Xbenzene = 0.30 at its boiling point. If the activity coefficient of benzene in this solution were actually 0.93 rather than 1.00, what would be its vapor pressure?

  • 1) Benzene and toluene form nearly ideal solutions. At 20°C the vapor pressure of pure benzene...

    1) Benzene and toluene form nearly ideal solutions. At 20°C the vapor pressure of pure benzene is 74 torr and that of pure toluene is 22 torr. A solution consisting of 1.00 mol of each component is boiled by reducing the external pressure below the vapor pressure. Calculate (a) the pressure at which boiling begins and (b) the composition of each component in the vapor.

  • Benzene and toluene form nearly ideal solutions. If at 300K, P_ToI = 0.0422 atm and P_Benz*...

    Benzene and toluene form nearly ideal solutions. If at 300K, P_ToI = 0.0422 atm and P_Benz* = 0.136 atm. Compute the vapor pressure of a solution containing 0.6 mole fraction of toluene. Calculate the mole fraction of toluene in the vapor for this composition of liquid.

  • Vapor pressures of benzene and toluene

    Benzene and toluene form nearly ideal solutions. Consider an equimolar solution of benzene and toluene. At 20°C the vapour pressures of pure benzene and toluene are9.9 kPa and 2.9 kPa, respectively. The solution is boiled by reducing the external pressure below the vapour pressure.Calculate:(a) The pressure when boiling begins,(b) The composition of each component in the vapour, and(c) The vapour pressure when only a few drops of liquid remain

  • 10. Benzene ( C6H6 ) and toluene ( C6H5CH3 ) form ideal solutions. At 35°C the...

    10. Benzene ( C6H6 ) and toluene ( C6H5CH3 ) form ideal solutions. At 35°C the vapor pressure of benzene is 160. torr and that of toluene is 50.0 torr. If 3.6 mol of benzene and 5.5 mol of toluene are placed in a closed container at 35°C, what is the mole fraction of toluene in the vapor phase when equilibrium is reached? A) 0.52 B) 0.68 C) 0.32 D) 0.14 E) 0.60

  • please please answer both questions . Thank you !!! Question 9 (1 point) Benzene and toluene...

    please please answer both questions . Thank you !!! Question 9 (1 point) Benzene and toluene form an ideal solution. At 298 K, what is the mole fraction of benzene in the liquid that is in equilibrium with a vapor that has equal partial pressures of benzene and toluene? At 298 K, the vapor pressures of pure benzene and pure toluene are 95 and 28 tor respectively 0.50 0.77 0.23 0.30 none of these Question 10(1 point) 340.0 g of...

  • 4. (5 pts) Normal boiling point of benzene (C.H.) is 80.1 °C. If you add 0.15...

    4. (5 pts) Normal boiling point of benzene (C.H.) is 80.1 °C. If you add 0.15 moles of a nonvolatile solute to 250.0 g of benzene, what is the vapor pressure of the benzene at 80.1 °C?

  • Benzene, C6H6, and octane, C8H14, form an ideal solution. At 60°C the vapor pressure of pure...

    Benzene, C6H6, and octane, C8H14, form an ideal solution. At 60°C the vapor pressure of pure benzene is 0.507 atm, and the vapor pressure of pure octane is 0.103 atm. A solution is composed of 3.53 g of benzene, and 40.2 g of octane. What is the mole fraction of benzene in the vapor phase above the liquid? In order to receive full credit, your work should clearly show the following: a) the calculation of the partial pressure of benzene...

  • A mass m = 0.060 kg of benzene vapor at its boiling point of 80.1 °C...

    A mass m = 0.060 kg of benzene vapor at its boiling point of 80.1 °C is to be condensed by mixing the vapor with water at 44 °C. What is the minimum mass of water required to condense all of the benzene vapor? Assume that the mixing and condensation take place in a perfectly insulating container.

  • A mass m = 0.040 kg of benzene vapor at its boiling point of 80.1 °C...

    A mass m = 0.040 kg of benzene vapor at its boiling point of 80.1 °C is to be condensed by mixing the vapor with water at 39 °C. What is the minimum mass of water required to condense all of the benzene vapor? Assume that the mixing and condensation take place in a perfectly insulating container.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT