Question

Nb2O5 and Al can react as follows: 3Nb2O5(s) + 10Al(s) = 6Nb(s) + 5Al2O3(s). Theoretically, how...

Nb2O5 and Al can react as follows: 3Nb2O5(s) + 10Al(s) = 6Nb(s) + 5Al2O3(s). Theoretically, how many grams of Nb can a mixture of 11.60 g Nb2O5 and 2.60 g Al produce? Molar masses: M(Nb2O5) = 265.8 g/mol, M(Al) = 26.98 g/mol, and M(Nb) = 92.91 g/mol.

(A) 14.9 g (B) 8.95 g (C) 8.10 g (D) 5.37 g (E) 2.03 g

0 0
Add a comment Improve this question Transcribed image text
Answer #1

3 N62 Ost loal 6 Nb + 5 Al2O3 . mass: Now, moles of Nb₂ora molar mass 11.60g = 0.04.36 mol 265.8 glomolie 2.60 9 0.0964 mol .

Add a comment
Know the answer?
Add Answer to:
Nb2O5 and Al can react as follows: 3Nb2O5(s) + 10Al(s) = 6Nb(s) + 5Al2O3(s). Theoretically, how...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1. A 50.0 L gas mixture at T = 500 K contains 123.0 g H2 and...

    1. A 50.0 L gas mixture at T = 500 K contains 123.0 g H2 and 855.0 g CO. What is the total pressure of the mixture? Assume ideal-gas behavior. Molar masses: M(H2) = 2.016 g/mol, M(CO) = 28.01 g/mol. (A) 116 atm (B) 75.1 atm (C) 50.1 atm (D) 34.1 atm (E) 25.0 atm 2. KCl and K2SO4 are strong electrolytes. How do the concentrations of K+ ions, c(K+), in 2M KCl and 1M K2SO4 aqueous solutions compare? (A)...

  • Water can decompose into H, and 0, via electrolysis. How many moles of H, could theoretically...

    Water can decompose into H, and 0, via electrolysis. How many moles of H, could theoretically be obtained from 80.4 g of water. theoretical yeild: mol H, How many grams of Cl, are needed to form 76.8 g of AICI,? 2 Al(s) + 3 C1,(8) + 2 AICI, (s) Step 1: Show the strategy for solving this problem. grams Alci, → grams C1, Answer Bank grams AICI, moles C12 grams Al moles AICI moles Al grams Ch Step 2: Show...

  • can 4 Al(s) +30₂ (9) -> 2Al2O₃ (3) A what mass of Al 82.49 AL oxice...

    can 4 Al(s) +30₂ (9) -> 2Al2O₃ (3) A what mass of Al 82.49 AL oxice (101.96gimoi) beform 26.98 g/mol 117.65g o B What is the long limiting realant? 32.oog mol C) obtain 117.1 g of Al2O3(5) What is the recent Yeild of their reaction? (oo)

  • How many grams of A1,0, can form from 35.8 g of Al? 4 Al(s) + 30,(8)...

    How many grams of A1,0, can form from 35.8 g of Al? 4 Al(s) + 30,(8) +2A1,03(s) Step 1: Show the strategy for solving this problem. grams Al - grams A1,03 :50 : PARTNER Answer Bank moles 0 grams 0 moles Al grams Al grams A1,0, moles Al,O, Step 2: Show the conversions required to solve this problem and calculate the grams of A Step 2: Show the conversions required to solve this problem and calculate the grams of A1,0,....

  • When solid magnesium is reacted with an aluminum phosphate solution, metallic aluminum is produced by single...

    When solid magnesium is reacted with an aluminum phosphate solution, metallic aluminum is produced by single displacement (equation. a): (a) AlPO​4​​(aq)+Mg(s)→Al(s)+Mg​3​​(PO​4​​)​2​​(aq) Balance equation (a) and answer the following: How many grams of aluminum metal should be theoretically produced from 2.338 g of pure magnesium metal. Suposse magnesium metal is the limiting reactant. Molar masses (g/mol): AlPO4 = 121.95 Mg = 24.305 Al = 26.98 Mg​3​​(PO​4​​)​2 = 262.86 Important note: Use 3 digits after the decimal place in your answer.

  • Determine the number of grams of HCI that can react with 0.750g of Al(OH), according to the following reaction A...

    Determine the number of grams of HCI that can react with 0.750g of Al(OH), according to the following reaction Al(OH)3(s) + 3 HCl(aq) → AICI,(aq) + 3 H20(aq) STARTING AMOUNT ADD FACTOR 3 78.00 1 6.022 * 102 18.02 1.05 1 2.25 0.750 0.117 0.351 9.60 * 10 0.0288 36.46 133.33 g AICI g HCI mol HCI 9 Al(OH)3 g H30 mol H20 mol Al(OH)2 mol AICI mol AICI, GAICIS Determine the number of grams of HCI that can react...

  • 49. H2 and N2 react to form NH, by the equation: 3H2(g) + N2(g) → 2NH,(...

    49. H2 and N2 react to form NH, by the equation: 3H2(g) + N2(g) → 2NH,( g). If a reaction vessel initially contained 300 H, m 50 N2 molecules, which molecules would be prese and 1 if the reaction proceeds completely towards prodtupresent nt N molecules NHs molecules H2 molecules N molecules (A) O (B) 0 (C) 0 (D) 150 0 50 50 0 200 200 100 150 50. How many moles of Al2O, can Molar Mas be produced by...

  • Al(OH)3(s)+3HCl(aq)→AlCl3(aq)+3H2O(l) 1. Calculate the number of grams of HCl that can react with 0.440 g of...

    Al(OH)3(s)+3HCl(aq)→AlCl3(aq)+3H2O(l) 1. Calculate the number of grams of HCl that can react with 0.440 g of Al(OH)3. 2. Calculate the number of grams of AlCl3 formed when 0.440 g of Al(OH)3 reacts. 3. Calculate the number of grams of H2O formed when 0.440 g of Al(OH)3 reacts.

  • Iff possible answer both questions, thank you 50 (C) 0 (D) 150 0 150 50. How...

    Iff possible answer both questions, thank you 50 (C) 0 (D) 150 0 150 50. How many moles of Al,O, can Molar Mass be produced by the completeA reaction of 13.35 g of Al? g mot 26.98 4A1(s) + 3O2(g) → 2A 1203(s) (B) 0.9896 mol (D) 0.2474 mol (A) 6.675 mol (C) 0.4948 mol 51. What mass of C o2Ss is required Molar Mass / g mor to produce 88.0 g of solid Co Co2S3 58.93 214.1 cobalt? 2Co2S(s)...

  • please hep with clear steps ( SO I can learn how to do this) 1. If...

    please hep with clear steps ( SO I can learn how to do this) 1. If 5.00 g of pure Na2CO3is treated with HCl solution, how many grams of NaCl will be produced if the water is subsequently evaporated from the salt? Molar Mass ofNa 2CO3= 105.99 g/mol. 2. If 5.00 g of pure NaHCO3 is treated similarly, how many grams of NaCl will result?Molar Mass of NaHCO3= 84.01g/mol. 3. What volume of 3.00 M HCl would be required to...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT