1st calculate the heat required
Given:
m = 175 g
C = 4.184 J/g.oC
Ti = 20 oC
Tf = 80 oC
use:
Q = m*C*(Tf-Ti)
Q = 175.0*4.184*(80.0-20.0)
Q = 43932 J
Given:
lambda = 0.125 m
calculate energy of 1 photon
use:
E = h*c/lambda
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(0.125 m)
= 1.59*10^-24 J
number of photon = total energy/energy of 1 photon
n = 43932.0/1.59*10^-24
= 2.763*10^28
Answer: 2.76*10^28
need help hul See Periodic Table See Hint Suppose an oven's radiation wavelength is 0.125 m....
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