Homework Answers
Given:
Hof(HA(aq)) = 436.115 KJ/mol
Hof(MX2(aq)) = 132.96 KJ/mol
Hof(MA2(aq)) = -491.794 KJ/mol
Hof(HX(l)) = 323.735 KJ/mol
Balanced chemical equation is:
2 HA(aq) + MX2(aq) ---> MA2(aq) + 2 HX(l)
ΔHo rxn = 1*Hof(MA2(aq)) + 2*Hof(HX(l)) - 2*Hof( HA(aq)) - 1*Hof(MX2(aq))
ΔHo rxn = 1*(-491.794) + 2*(323.735) - 2*(436.115) - 1*(132.96)
ΔHo rxn = -849.514 KJ
Answer: -849.514 KJ
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5.
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where the heats of formation are given in the following
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D
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Express your answer in kilojoules.
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