Given:
Hof(H2S(g)) = -20.6 KJ/mol
Hof(H2O(l)) = -285.8 KJ/mol
Hof(H2(g)) = 0.0 KJ/mol
Hof(SO2(g)) = -296.8 KJ/mol
Balanced chemical equation is:
H2S(g) + 2 H2O(l) ---> 3 H2(g) + SO2(g)
ΔHo rxn = 3*Hof(H2(g)) + 1*Hof(SO2(g)) - 1*Hof( H2S(g)) -
2*Hof(H2O(l))
ΔHo rxn = 3*(0.0) + 1*(-296.8) - 1*(-20.6) - 2*(-285.8)
ΔHo rxn = 295.4 KJ
Answer: 295.4 KJ
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