The change of enthalpy and entropy of the reaction is calculated:
ΔH = ΔHf products - ΔHf reagents = (3 * 0) + (-110.4) - (-74.8) - (-241.6) = 206 kJ / mol
ΔS = (3 * 130.7) + 197.9 - 186.3 - 188.8 = 214.9 J / K * mol
The free energy change is calculated:
ΔG = ΔH - T * ΔS = 206 - 298 * 0.2149 = 142 kJ / mol
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