Question

Calculate enthalpy change using standard heats of formation. Using the standard heats of formation that follow, calculate the standard enthalpy change for the following reaction. S(s.rhombic) + 2CO(g) +SO2(g) + 2C(s.graphite) Hºrn Species AH% (kJ/mol) CO(g) -110.5 SO2(g) 296.8

Answer 1

11 11 11 Standard enthalpies of formation AH°il S (s) ) = 0.0 kJ/mol AHºfl co (g) ) = -110.5 kJ/mol AHºfl s02 (g) ) = -296.8 kJ/mol Ahºr ( C (s) ) = 0 kJ/mol 1 S (s) + 2 co (g) → A Hºreactents = ( 1 X 0.0 ) + ( 2 AH°products = ( 1 % -296.8 ) + ( 2 AHrxn = AH°products - A Hºreactents AHrxn = ( -296.8 )-C -221.0 ) = N X 1 SO2 (g) + 2 C (s) X -110.5 ) = -221 kJ/mol * 0.0 ) = -296.8 kJ/mol -75.8 kJ