Part of an ANOVA table is shown below.
Source of Variation |
Sum of |
Degrees of |
Mean |
F |
Between Treatments |
180 |
3 |
||
Within Treatments (Error) | ||||
TOTAL |
480 |
18 |
The mean square due to error (MSE) is
a. |
60. |
|
b. |
15. |
|
c. |
20. |
|
d. |
18. |
Error Sum of squares = 480 - 180 = 300
Error degrees of freedom = 18 - 3 = 15
Hence,
Mean square due to error = 300/15 = 20
Option C is correct.
Part of an ANOVA table is shown below. Source of Variation Sum of Squares Degrees of...
Exhibit 13-5 Part of an ANOVA table is shown below. Source of Variation Sum of Squares Degrees of Freedom F Mean Square 180 3 Between treatments Within treatments (Error) Total 480 18 Refer to Exhibit 13-5. The mean square between treatments (MSTR) is a. 300 b. 60 O c. 15 O d. 20
Part of an ANOVA table is shown below. Source of Variation Sum of Squares Degrees of Freedom Mean Square F Between Treatments 64 8 Within Treatments (Error) 2 Total 100 The number of degrees of freedom corresponding to between-treatments is a. 3. b. 4. c. 2. d. 18.
#16 The test statistic is a. 6.00. b. 2.25. c. 3.00. d. 2.67. #17 The mean square due to error (MSE) is a. 60. b. 18. c. 15. d. 20. Part of an ANOVA table is shown below. Sum of Degrees Squares Freedom Mean of Source of Variation Square 180 Between Treatments Within Treatments (Error) TOTAL 480 18
Source of Variation Sum of Squares Degrees of Freedom Mean Square F Between Treatments 180 3 Within Treatments (Error) TOTAL 480 18 If at 95% confidence, we want to determine whether or not the means of the populations are equal, the p-value is between 0.01 to 0.025 between 0.025 to 0.05 between 0.05 to 0.1 greater than 0.1
Use the following for questions 5,6,7,8, and 9. Part of an ANOVA table is shown below. Source of Sum of Degrees of Mean F p-value Variation Squares Freedom Square Treatments 180 3 Error 16 Total 480 19 The number of treatments (i.e. groups) in the experiment is a.4 b.3 c. 19 d. 16 The mean square between treatments (MSTR) is a. 18.75 b. 60 c. 300 d. 16 The mean square due to error (MSE) is a. 60 b. 16...
Exhibit 13-7 The following is part of an ANOVA table, which was the result of three treatments and a total of 18 observations (6 observations per sample). Source of Variation Sum of Mean F Degrees of Freedom Squares Square Between treatments 64 Within treatments (Error) 96 Total 1) Refer to Exhibit 13-7. The number of degrees of freedom corresponding to between treatments is 2) The number of degrees of freedom corresponding to within treatments is 3) The mean square between...
0.0.2702 QUESTION 17 Consider the following partial ANOVA table. Source of variation df Sum of squares Mean squares Treatments Error Total 6.67 75 60 19 135 25 3.75 The numerator and denominator degrees of freedom (identified by asterisks) are, respective 1. 4 and 15 2. 3 and 16 3. 15 and 4 4. 16 and 3 5. 4 and 8
Source of Variation Sum of Squares Degrees of Freedom Mean Square F Between Treatments 64 8 Within Treatments 2 Error Total 100 If at 95% confidence we want to determine whether or not the means of the populations are equal, the p-value is greater than 0.1 between 0.05 to 0.1 between 0.025 to 0.05 less than 0.01
e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest whole numbers. Round all Mean Squares to one decimal places. Round F to two decimal places. Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatments Error Total f. At the α-.05 level of significance, test whether the means for the three treatments are equal The p-value is less than.01 What is your conclusion? Select The following data are from a...
Mean Square (Variance) Degrees of Sum of Source Freedom Squares Consider an experiment with nine groups, with eight values in each. For the ANOVA summary table shown to the right, fill in all the missing results. Among FSTAT ? MSA 22 SSA ? c-1 ? groups Within MSW ? SSW 693 n c groups Total SST ? n-1 2 Complete the ANOVA summary table below. Degrees of Freedom Sum of Mean Square (Variance) MSA 22 Source Squares FSTAT Among groups...