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Use the following for questions 5,6,7,8, and 9. Part of an ANOVA table is shown below. Source of Sum of Degrees of Mean F p-v
The mean square between treatments (MSTR) is a. 18.75 b. 60 c. 300 d. 16
The mean square due to error (MSE) is a. 60 b. 16 c. 300 d. 18.75
The test statistic is a. 2.25 b. 6 c. 2.67 d. 3.2
If the p-value is 0.0517 and a = 0.01 (the level of significance), the conclusion of the test is that the population means a.
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Answer #1

Solution

The complete anova table is obtained

Source of variation Sum of Squares Degrees of freedom Mean Square F P-value
Treatment 180 3 60 3.2 0.051703
Error 300 16 18.75
Total 480 19 25.26316

a. Number of treatment = 4

b. Mean Square between treatment = 60

c. Mean Square due to error = 18.75

d. The test statistic = 3.2

e. since p-value= 0.0517 > 0.01 so we conclude that population means may be equal.

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