Question

Using standard heats of formation calculate the standard enthalpy change for the following reaction. CO(g) + 3H2(9)+CH_(g) + H2O(g) ANSWER:

Answer 1

CO(g) + 3H₂(g) - CHu (g) CHu (g) + H₂O (9) Useful standard shi (com) Dhe (Hego) DH (Chug) DHI (H₂O) heat of formations value:- -110.54 kJ/mol 0 kJ/mol - 74.85 kJ/mol - 241.81 kJ) meel. EDH reactants Dhix = EAH products = (staro + At noo) - (Arenut 3x AHA) =(-74.85 – 2418) 241-81) -(-110.54+ 3xo) 3. - 316.66 + 110.54 - 206.12

2 50₂(g) + O₂(g) -> 2503 (8) Useful standard heat of formations - 395.72 kJ / meel DH so se - 296.82 kJ/mol SO2(g) DH 029) 0 kJ/mol. AHåxn = EDH products E alreactants [2x(-395:12)] - [2xl-296.82) + o] = - 791.44 +593.64 Dhiren -197.8 KJ

2 C₂ H₂ (9) + 702(g) 4 CO₂ (g) + 6H₂O (9) Given in DH rxu = - 2847.0 KJ Useful standard enthalpies of formation SHO 0 kJ/mol 02(8) A H cong - 393. 50 kJ/mol A Hilog = – 241.81 kJ/mol + 02199 DHåxn = EDM products - {All reactants - Olho = (4XA How 6 X AH10) - (2x DH smo 09 + 76 40 >> - 2847.0 - [4xC-393-80) + 6X(-241-81)) - (2x Datum + 7% > -2847.0 = (-1574.0 - 1450.86) - 2xD Heatinas 7x0) - 2847.0= -30 24.86 - 2 X DHC CHOCO 3024.86 + 2847.0 2x D HC Holg - 2x DH CHO -177.86 DH CHO - 88.93 kJ/mol