Question

7) The reaction of peroxydisulfate ion (S₂O₈²⁻) with iodide ion (I⁻) is

S2O82−(aq) + 3I−(aq) → 2SO42−(aq) + I3−(aq)

From the following data collected at a certain temperature, determine the rate law and calculate the rate constant.

Experiment	[S2O82−](M)	[I−](M)	Initial Rate [M/s]
1	0.0200	0.0960	7.60 × 10−4
2	0.0200	0.0480	3.80 × 10−4
3	0.0400	0.0480	7.60 × 10−4

(a) Which of the following equations represents the rate law for this reaction?

A. rate = k[S2O82−][I−] .		C. rate = k[S2O82−][I−]2
B. rate = k[S2O82−]2[I−]		D. rate = k[S2O82−]2[I−]2

(b) What is the rate constant for the reaction?

a) k = _______ /M · s

Answer 1

Let sate land be R= K [5,08 ")" [19" © 7.68164 K (0.02)990.096) ☺ 3.8X104 = K 10.02)“ (6.04675 ® 7.681042 k 10.04)" (0.64875 ☺o. se tisa 1 2 » 6=10 i - 3 .8 | ®/ 0.29 us azt putting values of ait in ① 746X10-4 ms7 = K (0.02mg 10.095m) ike 04396 M7's? a: Rok 13,0893117) 1. Ang A LSI - b. k= 0.0396/MS 3 .