Question

Two metal bars experience an equal change in volume due to an equal change in temperature. The first bar has a coefficient of expansion twice as large as the second bar. How does the original volume of the first bar compare to the original volume of the second bar? Enter your response Why? Comes from 13.2 Thermal Expansion of Solids and Liquids

Answer 1

Expansion in volume with respect to temprature we can be written in this way:-

$V= V_{o}(1+\gamma t)$

here gamma is coeffecient of thermal expansion

$V= V_{o}(1+\gamma t)\\ \gamma _1 = 2\gamma_2$

So as we increase the temprature Volume of first bar change much faster than comapare the second bar.