Homework Answers
From the scale -
Horizontal distance between Q1 and Q2, x = 9.5 cm - 3.5 cm = 4.0 cm
Here, vertical axis is not shown in the enclosed picture. It must be given in your problem.
I am just considering the vertical distance between the two charges, y = 3.0 cm
So, distance between the two charges Q1 and Q2, r = sqrt[x^2 + y^2]
= sqrt[4.0^2 + 3.0^2] = 5.0 cm = 0.05 m
Now, expression for the electrostatic force by the charge Q2 on the charge Q1 is given as -
F = k*Q1*Q2 / r^2 = (9.0 x 10^9 x 1.40 x 10^-9 x (-6.30 x 10^-9)) / 0.05^2
= -3.175 x 10^-5 N
Negative sign shows that there will be force of attraction between the two charges.
Add Answer to:
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