Question

1. Calculate AHL of Ag2S using each of the following methods. You will need to look up ionization energies, AHEA, AH and radi

Assume that Ag2S forms a rutile structure with A = 2.406

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Answer #1

Fig. Born Haber cycle for Ag2S

-∆Hf0 + 2∆Hsub(Ag) + ∆Hsub(S) + 2I.EAg+ + E.A1 + E.A2 +∆HL = 0

∆HL = ∆Hf0 - 2∆Hsub(Ag) - ∆Hsub(S) - 2I.EAg+ - E.A1 - E.A2

∆HL = -31.8 -2(255) -9.8 – 2(731)- 200+ 456

∆HL = -31.8-510-9.8- 1462- 200-456

∆HL = -2669.6 KJ/mol

  1. From Born-Lande equation we have,

∆G = -ANz2e24πϵor(1- -1n)

∆G = - 2.4 x (6.023 x10+23) x 1x 2 x(1.6x10-19)24 x 3.14 x 8.854x 10-12 x 2.406x 10-10X(1-110)

∆G = - 2489.5 KJ/mol

  1. From Born-Mayer equation we have,

∆G = -NMz2e24πϵr(1- -34.5 x 10-12r)

∆G = -6.023 x10+23x 2.4 x 1x 2 x(1.6x10-19)24 x 3.14 x 8.854 x 10-12 x 2.406x 10-10X(1-34.5 x 10-122.406x 10-10)

∆G = - 2370 KJ/mol

  1. From Kaputinskii equation we have,

UL = 1.202X10-4 nZ+Z-r 1-34.5 x 10-12r

UL = - 2568 KJ/mol

    Method

    Lattice energy (KJ/mol)

    Born Haber Cycle

    -2669.6

    Born Lande equation

    -2489.5

    Born Mayer equation

    - 2370

    Kaputinskii Equation

    -2568

    Born Haber cycle is most accurate among these methods because it considers all the possible physical and chemical changes during the formation of the lattice.

    Kaputinskii method is the easiest to carry out.

    1. Silver sulfide is the inorganic compound with the formula Ag2S. A dense black solid, it is the only sulfide of silver. It is useful as a photosensitizer in photography. It constitutes the tarnish that forms over time on silverware and other silver objects. Silver sulfide is insoluble in most solvents, but is degraded by strong acids. Silver sulfide is a network solid made up of silver (electronegativity of 1.98) and sulfur (electronegativity of 2.58) where the bonds have low ionic character (approximately 10%).

    Sources

    Wikipedia

    Periodictable.com

    Chemlibretexts.org

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