If a capacitor has 2.82 μC of charge on it and an electric field of 2.10...
Area of a Capacitor FR If a capacitor has 4.64 μC of charge on it and an electric field of 2.41 kV/mm is desired if they are separated by 3.93 mm of air, what must each plate's area be? Submit Answer Tries 0/10
Part A If a capacitor has opposite 5.0 μC charges on the plates, and an electric field of 2.4 kV/mm is desired between the plates, what must each plate's area be? Express your answer using two significant figures and include the appropriate units. Part B How much kinetic energy will an electron gain (in joules) if it accelerates through a potential difference of 1.69×104 V ? Part C How much kinetic energy will an electron gain (in eV) if it...
Constants The electric field between the plates of a paper- separated (K 3.75) capacitor is 8.19x104 V/m. The plates are 2.20 mm apart, and the charge on each plate is 0.685 μC Determine the capacitance of this capacitor Express your answer using three significant figures and include the appropriate units. IA C Value Units Submit Request Answer ▼ Part B Determine the area of each plate Express your answer using three significant figures and include the appropriate units.
The electric field between the plates of a paper-separated (K=3.75) capacitor is 8.24×104 V/m . The plates are 1.75 mm apart, and the charge on each plate is 0.700 μC Determine the capacitance of this capacitor. Determine the area of each plate.
The electric field between the plates of a paper-separated (K=3.75) capacitor is 8.23×104 V/m . The plates are 1.75 mm apart, and the charge on each plate is 0.705 μC . Determine the capacitance of this capacitor. Determine the area of each plate
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.10 mm. A 25.0-V potential difference is applied to these plates (a) Calculate the electric field between the plates kV/m (b) Calculate the surface charge density. nc/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate pc
A parallel-plate air capacitor has a capacitance of 300 pF and a charge of magnitude 0.150 μC on each plate. The plates are 0.500 mm apart. A. What is the potential difference between the plates? Answer: V=500V B. What is the area of each plate? C. What is the electric-field magnitude between the plates? D. What is the surface charge density on each plate?
19.17 Electric Potential in a Uniform Electric Field What is the electric field strength between two parallel conducting plates if the plates are separated by 2.30 mm and a potential difference of 4.9x 10 V is applied? Does the electric field strength exceed the breakdown strength for air (3.0x10° V/m)i? Yes No Submit Answer Tries o/10 How close together can the plates be with this applied voltage? Submit Answer Tries 0/10
How strong is the electric field between the plates of a 0.60-μF air-gap capacitor if they are 1.0 mm apart and each has a charge of 71 μC ?
An electric charge of 2.10 μC
is at rest at the origin. An electric force of 63.9×10-6 N acts on
the charge as shown in the figure. What is the x-component of the
electric field at the origin? (Note: 1 V/m = 1 N/C) (in V/m) A:
9.785 B: 1.145×101 C: 1.339×101 D: 1.567×101 E: 1.834×101 F:
2.145×101 G: 2.510×101 H: 2.937×101
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