Alright Dude, If that worked for you... dont forget to give THUMBS UP.(that will work for me!)
If I missed something feel free to leave a comment.
atleast before giving downvote.
and, Thanks for using homeworklib- Smarter way to study.
Area of a Capacitor FR If a capacitor has 4.64 μC of charge on it and...
If a capacitor has 2.82 μC of charge on it and an electric field of 2.10 kV/mm is desired if they are separated by 4.74 mm of air, what must each plate's area be? Submit Answer Tries 0/10
Part A If a capacitor has opposite 5.0 μC charges on the plates, and an electric field of 2.4 kV/mm is desired between the plates, what must each plate's area be? Express your answer using two significant figures and include the appropriate units. Part B How much kinetic energy will an electron gain (in joules) if it accelerates through a potential difference of 1.69×104 V ? Part C How much kinetic energy will an electron gain (in eV) if it...
A parallel-plate air capacitor has a capacitance of 300 pF and a charge of magnitude 0.150 μC on each plate. The plates are 0.500 mm apart. A. What is the potential difference between the plates? Answer: V=500V B. What is the area of each plate? C. What is the electric-field magnitude between the plates? D. What is the surface charge density on each plate?
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.80 mm. If a 17.0 V potential difference is applied to these plates, calculate the following. (a) the electric field between the plates _______ kV/m (b) the capacitance _______ pF (c) the charge on each plate _______ pC
An air-filled parallel-plate capacitor has plates of area 2.50 cm2 separated by 3.00 mm. The capacitor is connected to a 21.0-V battery. (a) Find the value of its capacitance. (b) What is the charge on the capacitor? (c) What is the magnitude of the uniform electric field between the plates?
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 25.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. kV/m (b) Calculate the surface charge density. nC/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate. pC
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.10 mm. A 25.0-V potential difference is applied to these plates (a) Calculate the electric field between the plates kV/m (b) Calculate the surface charge density. nc/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate pc
An air-filled parallel-plate capacitor has plates of area 2.70 cm2 separated by 0.50 mm. The capacitor is connected to a 6.0-V battery. (a) Find the value of its capacitance. ________ pF (b) What is the charge on the capacitor? ________ pC (c) What is the magnitude of the uniform electric field between the plates? ________ V/m
An air-filled parallel-plate capacitor has plates of area 2.80 cm^2 separated by 2.50 mm. The capacitor is connected to a(n) 17.0 V battery. Find the value of its capacitance. _____ pF What is the charge on the capacitor? ______ pC What is the magnitude of the uniform electric field between the plates ___________ N/C
A parallel-plate capacitor with plate area 4.60 cm2 and air-gap separation 0.78 mm is connected to a 12.00 V battery, and fully charged. The battery is then disconnected. (a) What is the charge on the capacitor? (b) The plates are now pulled to a separation of 0.98 mm. What is the charge on the capacitor now? (c) What is the potential difference across the plates now? (d) How much work was required to pull the plates to their new separation?...