3. Consider a 0.586 M aqueous solution of barium hydroxide, Ba(OH)2 (aq). How many grams of...

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Answer 1

Answer #1

volume = 0.191 dL = 0.0191 L

molarity = 0.586 M

moles = molarity x volume

= ( 0.586 mol / L ) x ( 0.0191 L )

= 0.01119 moles

molar mass of Ba(OH)2 = 171.34 g / mole

mass = 0.0119 x 171.34 = 1.92 g

mass = 1.92 g

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Answer 2

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