You have 210.5 g of Ba(OH)2.
1. How many moles of barium hydroxide, Ba(OH)2, are present in 210.5g?
2. How many moles of hydroxide ions are present in Part 1?
Molar mass of barium hydroxide = 171.34 g/ mol
Moles of barium hydroxide, Ba(OH)2, are present in 210.5g = 210.5/171.34 = 1.2285 moles.
Since one mole of barium hydroxide will give two mole of hydroxide ions , moles of hydroxide ions are present in Part 1
= 2 x ( 1.2285 ) = 2.45 7
You have 210.5 g of Ba(OH)2. 1. How many moles of barium hydroxide, Ba(OH)2, are present...
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