Question

Constants For the capacitor network shown in (Figure 1), the potential difference across ab is 200 V Figure 〈1of1 〉 35 nF 75 nF

PART A

Find the total charge stored in this network.

PART B

Find the charge on the 35 nF capacitor.

PART C

Find the charge on the 75 nF capacitor.

PART D

Find the total energy stored in the network.

PART E

Find the energy stored in the 35 nF capacitor.

PART F

Find the energy stored in the 75 nF capacitor.

PART G

Find the potential difference across the 35 nF capacitor.

PART H

Find the potential difference across the 75 nF capacitor.

Answer 1

V = 200volt q = c nu q = (c_1 + c_2) nu q = (110 times 10^-9 times 200) = 220 times 100 times 106-9 (A) q = 2.20 times 10^-5 C (B) q_1 = c_1 nu = 35 times 200 times 10^-9 q = 0.7 times 10^-5C (C) q_2 = 75 times 200 times 10^-9 q_2 = 1.5 times 10^-5C (D) Total energy = 1/2 v^2 = 1/2 times 110 times 10^-9 times (200)^2 E = 2.2 times 10^-3 J (E) Energy in 35nf = 1/2 times 35 times 10^-9 times (200)^2 E_1 = 7 times 10^-4 J (F) E_2 = 1.5 times 10^-3 J (G) v_1 = 200volt (H) v_2 = 200volt