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qual 5 In this case? Why or why not? 5.8. The hemoglobin in blood establishes an equilibrium with oxygen gas very quickly. Th
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Answer #1

Let us denote the reaction constant for the O2 binding as KO2 and that for CO binding as KCO.

The reaction for Oxygen is.

heme +02= heme. 0

Here, the equilibrium constant is given as,

Theme. 021 Ko2 = Theme

Here, big bracket [] denotes the concentration.

The reaction for Carbon monoxide is-

heme + CO=heme . CO

Here, the equilibrium constant is given as,

[heme.co [heme] CO]

In blood, [heme] is same for Oxygen and Carbon monoxide. Further, we assume that Carbon Monooxide and Oxygen is present in the same concentration. Then, dividing (2) by (1), we have,

[hете • со Theme 02 [heme. Co Theme 021 Kco Ко, 2.3 x 1023 9.2 x 1018 = 25000

This means that at same concentration, Carbon monoxide can bind 25000 times more than the Oxygen.

Thus, higher the value of equilibrium constant, higher is the binding capacity of the gas and the Further the equilibrium lies towards the product. Thus, equilibrium for the second reaction involving CO lies further towards the product. As can be seen from the calculations, Carbon monoxide can bind to heme 25000 times better than the Oxygen. This will mean that CO will take up most of the heme itself by binding to it leaving a small number of heme for O2. Thus, due to reduction in oxygen carrying capacity of heme in the blood, organs stop getting Oxygen and hence CO is a toxic gas,

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