According to HOMEWORKLIB RULES we have to answer only first one problem
The freezing point depression is given by:
T = k b i
Where:
T = freezing point depression , 2.83 K
k = cryoscopic constant ;1.853 °K /m
The Kf for water is 1.853 K·kg/mol
b = molality (moles of solute per kg of solvent)
i = van't Hoff factor, r
Number of moles = amount in g / molar mass
= 40.7 g/ 271.52 g/mol
=0.1499 moles
Mass of water = 100 g or 0.100 kg
Molality = number of moles / solvent in kg
=> m =0.1499 moles /0.100 kg
= 1.499 m
Therefore calculate the i as follows:
T = k b i
2.83 K = 1.853 °K /m*1.499 m *i
i = 1.0
the value of i is 1 means it is not ionize thus it is an example of weak electrolyte which will not conduct electricity
there is no ions
Weak electrolytes:
Weak electrolytes are partially ionizes in water.
Strong electrolytes have following properties:
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